Last Updated on Thursday, 14 January 2016 10:17 Written by Matematika - SD Kelas 4 Monday, 29 September 2014 14:01
Contoh soal :
Hitung keliling dan luas jajargenjang ABCD berikut ini!
Jawab:
Pada ΔBEC, siku-siku di E, diperoleh:
t2 = 132 – 52 = 169 – 25 = 144
t = √144 = 12 cm
Keliling jajargenjang ABCD = 2 × (AB + BC)
= 2 × (22 + 13)
= 2 × 35
= 70 cm
Luas jajargenjang ABCD = AB × BE
= 22 × 12
= 264 cm2
Dikutip dari buku Three In One Matematika Jilid 4.
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